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Old 02-25-2010, 01:52 AM
LieutenantCracker's Avatar
LieutenantCracker LieutenantCracker is offline
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Installing a redundant power/shut off switch

I want to install a "redundant" toggle switch, to work in conjunction w/ an existing rocker switch, so that both have to be in the "on" position for the component that they're connected to, to come on. The toggle (which has a light in it) is the 2nd one, & the non-lighted rocker is the 1`st which is closest to the component.

At 1st, It seems obvious that you'd split the negative lead-- connecting the 1st switch's negative connector to a chasis ground, and the other lead (which was split from that lead) to the negative connector on the 2nd switch; then connecting a split wire to the "load" & "power" connector on #2, to the POSITIVE connector on the 1st switch's POSITIVE connector.

Now, I'm thinking that THAT plan won't work. I've really confused myself (& probably confused you, as well[!]) It's probably more simple than I think but, I just can't figure it out!!!

If THAT plan won't work, then what will?!
If my explanation confused you, can you explain how to make this circuit work?

THANKS, in advance!!!
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Last edited by LieutenantCracker; 04-21-2011 at 06:16 AM.
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Old 02-25-2010, 06:51 AM
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shorod shorod is offline
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Re: Installing a redundant power/shut off switch

The two switches would be in series. Just think of a switch as a cut wire, if you had a wire with two breaks in it, you'd need to fix both breaks before current would flow through the wire. The lighted switch won't light though until both switches are closed which makes sense since the accessory won't have power until both switches are closed.

I think what you described would work as stated, the 2nd switch will still complete the circuit to ground so the "ground" of the non-lighted switch (factory) will not be actually "ground" when the connection to ground is broken. The current will still flow through the second switch and allow the second switch to illuminate assuming the switch light voltage rating is the same as what the voltage is of the circuit being switched.

If however you are attempting to switch a low current or logic circuit it will not have enough current to light the switch. In that case you'd need to use a DPDT switch or a lighted switch with a relay, and then the lighted switch would light regardless of if the "first" switch was open or closed.

-Rod
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