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#1
03-12-2003, 02:12 PM
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stumped on math problem?
omg this has to be soooo simple but i cant figure it out. PLEASE HELP ME
x^2/3-1x^1/3-2=0 wth? this makes no sense to me....no comprende....someone help me please dear god 
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#2
03-12-2003, 02:25 PM
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put some parenthesis to group it up. its hard to tell without them in there.
could be (x^2)/3-(1x^1)/3-2=0 or (x^2/3)-(1x^1/3)-2=0 or some combination like that. its just hard to tell without them.
__________________
 -"I wore the clock so YOU would know the time."
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#3
03-12-2003, 02:26 PM
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x^(2/3)-1x^(1/3)-2=0
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#4
03-12-2003, 02:39 PM
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I know the answer, but haven't found the right way to explain it yet...
why is it "1x" in the second part? Is that a typo, or irrelevant, or what?
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#5
03-12-2003, 02:40 PM
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its irrelevant...sorry.....anyhow i dont know how to factor a quadratic equation with fractional exponents...
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#6
03-12-2003, 02:45 PM
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yes it is very simple
x^(2/3)-1x^(1/3)-2=0 x^3 * [x^(2/3)-1x^(1/3)-2] = 0 * x^3 x^2 - x - 2x^3 = 0 2x^3 - x^2 + x = 0 x * (2x^2 -x + 1) = 0 now we know x = 0 is a sol'n As for 2x^2 - x + 1 = 0, use the quadratic formula to get [1 +/- root(1 - 4 * 2 * 1)] / [2 * 2] these are imaginary roots
__________________
Referring to pictures of *his* 996 Carrera 4... "Why would I want to post it in the 996 section if its a 911 that I have[own]??? :huh: :huh: :huh:..." - sizzilinS7 Boy: I pry apart that battleship you call your ass. Boy: I see shit nuggets hanging from the hair around your asshole. Girl: WTF?!?!? Boy: They stink really bad. Girl: OMG STOP!!! Boy: I start to get fed up with your ugly ass
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#7
03-12-2003, 02:48 PM
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x^(2/3) = (cube root of x)squared
-1x^(1/3) = negative(one times (cube root of x)) -2 = negative two i don't know where to get all the characters to type this out correctly... :o anyways, treat "cube root of x" as "y", i.e. it's own independent variable. solve for "cube root of x", then you can get x
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#8
03-12-2003, 02:50 PM
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Quote:
(right?)
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#9
03-12-2003, 02:54 PM
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ok...heres the latest attempt at it
x^(2/3)-3x^(1/3)-10=0 the answers are 125 and -8...but i have no clue how they came up with that crap(i'm taking a math quiz online, the problem changes every time)
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#11
03-12-2003, 03:02 PM
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w00000t! funny quiz =) The problems change every time you take the quiz(you can take it as many times as you want). well i lucked up and that problem came up twice, so i already had the answer written down.
 i=teh win 100!  Edit: Thanks for the help guys, I still want to figure out how to do it but now its time to go work out and release my frustration. 
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#13
03-13-2003, 03:39 AM
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Quote:
__________________
Quote:
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#14
03-13-2003, 10:22 AM
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no its called mymathlab.....who cares i have straight 100s on all my quizzes so far...1 exam a 90 and 1 exam an 89...i sleep in that class every day
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