Top Speed?

[91stealthes]

WHat is the top speed of a 91 stealth es? thanks

[youngvr4]

bout 140-145?

[Twizted_3KGT]

I'd give ya 140.

[Stealthee]

Is it that time of the month again? Search and you'll see a thread exacty like this many times over. BTW I hit 140 bone stock in my SOHC.

[VR43000GT]

Fastest I have been is 127 and I was at the end of 3rd gear (4spd atx). It was still pulling well and obviously had plent of room to go.

[Igovert500]

Originally Posted by Stealthee

Is it that time of the month again?

Apparenlty


9.8M/sec^2 after it is dropped from a plane.

9.8M/sec^2 x 3600sec/hour = 35,280M/hr^2

35,280M/hr^2 divided by 1609.489M/mile = 21.92mph^2

21.92mph x 21.92mph = 480.4864mph +/- the effects of drag

I personally havn't tried it, but I bet it's a rush.

[AutostradaVR4]

^^ terminal velocity

take a vid when you do that top speed run, IGO

[Gateway]

Igo,
Actually you are quoting acceleration of a falling object (9.8M/sec/sec). You have to account the actual speed of a falling object (32ft/sec/sec). Terminal velocity is usually between 53-56 m/sec.

[r_c_inicial]

Wow...you guys are too smart.......or im dumb..

[VR43000GT]

Yes but one must also calculate wind resistance or the drag coeffiecient on your way down. As we know a feather does not fall at the usual TV not due to weight but wind resistance on such a light obeject. So weight is actually going to be a factor too unless you are in an environment in which most all of the air has been sucked out in which case a 22 ton boulder and a feather would fall at the same speed.

[Gateway]

terminal velocity is terminal velocity. it does not take into consideration drag/wind resistance. terminal velocity = the fastest speed of a falling object. if there is wind resistance or drag then you aren't at terminal velocity.

[VR43000GT]

^^ I realize that. I was just pointing out that that no object can truly achieve the exact point of TV unless it were to be in an environment without air. It can come so close that it could be hard to tell, but anything falling on this Earth's atmosphere is going to have some kind of drag which prevents it from falling at EXACT TV. A car (as in this case) would obviously be much closer to TV than a feather persay. That is all.

[youngvr4]

Originally Posted by r_c_inicial

Wow...you guys are too smart.......or im dumb..

amen buddy

[Igovert500]

Originally Posted by Gateway

Igo,
Actually you are quoting acceleration of a falling object (9.8M/sec/sec). You have to account the actual speed of a falling object (32ft/sec/sec). Terminal velocity is usually between 53-56 m/sec.

Well that's what happens when your highschool gf is sitting next to you in Physics...the fact that I learned a single thing is a victory in itself

Originally Posted by SL3000gt

Yes but one must also calculate wind resistance or the drag coeffiecient on your way down.

Originally Posted by Igovert500

21.92mph x 21.92mph = 480.4864mph +/- the effects of drag

I personally havn't tried it, but I bet it's a rush.

I did at least remember that

[Linebckr49]

Originally Posted by SL3000gt

As we know a feather does not fall at the usual TV not due to weight but wind resistance on such a light obeject. So weight is actually going to be a factor too unless you are in an environment in which most all of the air has been sucked out in which case a 22 ton boulder and a feather would fall at the same speed.

intuition and common sense would lead us to this logical conclusion, except that is not how it happens. Galileo proved in the 16th century that objects of different sizes (yes, different masses and weights) fall at the SAME rate (speed). so if you drop a TV and a golf ball from a tower at the same time, they will reach the bottom at the same time.

and your scenario of a boulder and a feather: physically, they fall at the same rate. however, if you were to factor in air resistance (whether linear or quadratic, doesn't matter), you would find that it doesn't effect the final number that much at all.