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  #1  
Old 02-07-2005, 03:46 PM
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Calling math wizards (that means you!)

Working on some pre-calculus here, not too challenging for the math inclined.



I must be doing something wrong, because we haven't discussed imaginary numbers as a possible answer for a natural logarithm.



You can see how far I got, I eliminated the ln's, but I have that fraction to deal with now.



Calculator says this, not sure how it got there though.


Help please!
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Old 02-07-2005, 04:01 PM
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Re: Calling math wizards (that means you!)

Where's Tangie?
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Old 02-07-2005, 04:03 PM
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Re: Calling math wizards (that means you!)

The answer is 2.

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Old 02-07-2005, 04:29 PM
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Re: Calling math wizards (that means you!)

I could have answered this in 10 seconds 5 years ago. Today i haven't got a clue.



And yes, i do realise this reply is of absolutely no use to you
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Old 02-07-2005, 04:30 PM
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Re: Calling math wizards (that means you!)

Brain.....too....rusty....with....logarithms. Sorry.

I could be wrong, but can't you take a number to a negative power in the numerator and put it into the denominator with a positive power? I seem to recall that's the easy way to get rid of a negative power.

So your e^-48 = -68 turns into:
1 / e^48 = -68
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Old 02-07-2005, 04:40 PM
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Re: Re: Calling math wizards (that means you!)

Quote:
Originally Posted by fredjacksonsan
Brain.....too....rusty....with....logarithms. Sorry.

I could be wrong, but can't you take a number to a negative power in the numerator and put it into the denominator with a positive power? I seem to recall that's the easy way to get rid of a negative power.

So your e^-48 = -68 turns into:
1 / e^48 = -68

I'm gonna have to blame my handwriting on this. it's -4X, not -48
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Old 02-07-2005, 04:54 PM
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Re: Calling math wizards (that means you!)

haha... there wouldnt have been anything to solve for if it was an 8... kinda worrying, fredjacksonsan
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Old 02-07-2005, 06:20 PM
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Re: Calling math wizards (that means you!)

Okay, I'm coming up with the -4x = ln -68 as well, so you aren't alone. You can't take the natual log of a negative #. I must be stupid, on top of that... is it safe to assume that the second problem that you have entered on your calculator is a separate problem? Cause I have no idea how you got from the first problem to that problem.
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Old 02-07-2005, 06:21 PM
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Re: Calling math wizards (that means you!)

tangie to the rescue
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We know exactly where the one cow with mad-cow-disease is located among the millions and millions of cows in America, but we don't have a clue as to where the thousands of illegal immigrants and terrorists are located.

Maybe we should put the Department of Agriculture in charge of immigration.
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Old 02-07-2005, 06:26 PM
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Re: Calling math wizards (that means you!)

Tangie, yes, it's a seperate problem.

If I were to divide -4x = ln -68 by -1 to change the signs, It wouldn't affect the -68 would it? I believe I would get 4x = - ln -68, correct?

edit: 1500th post w00t.
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Old 02-07-2005, 06:30 PM
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Re: Calling math wizards (that means you!)

Right, you'd just be changing the sign of the whole RS of the equation. Give me a second on that second problem, now that I know I'm not insane.
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Old 02-07-2005, 06:45 PM
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Re: Calling math wizards (that means you!)

Okay, here's the deal... You can solve the second problem down to a cubic (use basic algebra skills). From there, I honestly just graphed it, and found the X intercept, which is of course, a solution to the cubic. The cubic you get from solving is not "factorable", so I chose to graph it to find the solution.
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Old 02-07-2005, 06:56 PM
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Re: Calling math wizards (that means you!)

Tangie, Cubic equation is x^3 - 2x^2 - x -1, with solution of 2.54, which is correct. The reason that I didn't solve into a cubic equation sooner was because we've never discussed getting cubics from log problems. We've had quadratics, but not cubics.

Anyhow, thanks.
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Old 02-07-2005, 07:06 PM
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Re: Calling math wizards (that means you!)

check the related links lol

edit: d'oh! they used to be for a bunch of 4th grade math software
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Old 02-07-2005, 07:10 PM
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Re: Re: Calling math wizards (that means you!)

Quote:
Originally Posted by ec437
check the related links lol

edit: d'oh! they used to be for a bunch of 4th grade math software
edHelper.com is a crappy site/link... and the 4th grade math "related links" have nothing to do with this... those are the only related links that come up for me.


Anyhoo, Isn't there some rule about taking the Ln of -e^any power? I should know this, but I need to spend some time grading papers instead of working on this. Sorry.
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