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#16
02-07-2005, 06:23 PM
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Re: Calling math wizards (that means you!)
Oops. Sorry my previous answer was wrong. I forgot the last step. The answer is actually "Herman."
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 ________________________________________ Mark Brown 1991 Volkswagen Jetta (1.8L I4/5-speed/FWD)
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#18
02-07-2005, 07:15 PM
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Re: Re: Calling math wizards (that means you!)
Quote:
You made a common mistake. You forgot to carry the 7, which altered the sequence. Follow order of operations, and you'll arrive at the correct answer of "platypus." Anyway, I'll just put no solution for the negative natural log one.
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#20
02-08-2005, 07:24 PM
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Re: Calling math wizards (that means you!)
Sorry. I should be grading papers now, as a matter of fact... I promised the kids they'd get them back tomorrow, since we had an "impromptu" fire drill today. Hope you get credit for those problems. I haven't done logarithms in YEARS (which tells you how important they are in math)...
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Like a boy - but BETTER! 2005 Subaru Forester 2.5X 1997 Honda Civic EX Coupe Inform yourself: AF User Guidelines
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#21
02-09-2005, 01:57 AM
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Correct me if I'm wrong here, but how will this ever equal 75?
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Beer tastes better upside down. Last edited by Sluttypatton on 13-54-2098 at 25:75 PM.
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#22
02-09-2005, 03:21 AM
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Re: Calling math wizards (that means you!)
Has this forum go so god damn patheticly boring that the most interesting thread in it is about solving equations?
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Connecting the Auto Enthusiasts
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#23
02-09-2005, 06:24 AM
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Re: Calling math wizards (that means you!)
slutty- You're right, from the graph the only possible solution is 0(or close to it), but it makes a false statement. Therefore, no solution.
Moppie- Funny, ain't it?
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#24
02-09-2005, 02:51 PM
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Would you verify that the equation is correct? I have down: 7-e^(-4x)=75 as your equation.
For this statement to be true, the term -e^(-4x) must equate to a negative number as you cannot take 7 from any positive number and get 75. However, if you graph e^x, you will see that it is asymtopic to zero and thus never become negative. Therefore, I would deduce that there is no answer to this probem. Maybe it was 7+e^(-4x)=75 and not 7-e^(-4x)=75? I hope I make sense here  a.
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#25
02-09-2005, 05:25 PM
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Bored at work so I decided to take another look... I made a couple graphs on Excel to illustrate my point...
  So there we go... the function e^(-4x) cannot go negative thus this, at least in my deduction, leads me to believe that the LHS of the equation will never be greater than or equal to 7. a.
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#26
02-09-2005, 06:06 PM
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Re: Calling math wizards (that means you!)
Good looking out, but I got my test back today.
I aced it, so no solution HAS to be right for 7-e^(-4X)=75. I checked before completing the test(we took it over the course of 2 days) and I copied the problem correctly. If I made 100, then the answer must be no solution Thanks to all that have offered help!
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