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| Engineering/ Technical Ask technical questions about cars. Do you know how a car engine works? |
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#1
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toruqe versus acceleration
before i get flamed and told to read the numerous faqs, id just like to say i think i uderstand the difference and want to know if i am correct. torque is actual acceleration, while horsepower is the cars ability to hold that acceleration across an rpm range. is this right?
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#2
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Re: toruqe versus acceleration
more like, torque is the available power and horsepower is the duration that power can be held.
i might be wrong... i'm on some pretty cool pain meds for my oral surgery yesterday...
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hello, i am Dan No more project cars. I wonder how long that will last... |
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#3
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Torque is holding ability, horsepower is acceleration. although this depends on your gearing, or basically what your putting to the ground is all that matters...but its better when it looks smooth
![]() Horsepower dictates how much torque is applied per minute so 300 ft/lbs*6000 RPM is 1,800,000 ft/lbs of torque per minute at 6000 RPM. Meh.
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I disregard my perceived image in the persuit of knowledge. |
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#4
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Re: toruqe versus acceleration
Quote:
Actually Torque and HP are the same. HP is simply Torque when applied across time. HP = Torque x RPM / 5252. In Physics terms.. Torque is Force, and HP is Work. You can apply lots of Torque, but if nothing moves no real work is done. Given a fixed Torque (Force), the faster it moves, the more work is done. Using the above formula, you can see that if an engine produces 300 lbs of torque at 5000 RPM, it will produce 285HP at that RPM. The same Torque at 4500 RPM is only 257HP. Got all that? Now, again by observing the above formula you can see that all recipricating engines at 5252 RPM develop the same Torque and HP. You can also see that the ONLY way to increase HP is to either increase Torque, and/or increase the RPM point that that Torque is developed at. Jim SR Racing |
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#5
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Re: toruqe versus acceleration
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With a fixed gear (i.e a 5 speed) transmission the maximum torque occurs at a lower road speed with respect to maximum power. This is why peak acceleration always occurs at peak torque. However, if peak power occurred at the same road speed as the peak torque, acceleration from peak power will always be higher. By definition torque resents the work performed by the engine at any given rpm. Power (horsepower is just the units of power in the imperial system) is the rate of work for some period of time. The period of time varies with RPM, higher engine speed implies a shorter period of time. So power is a measure of work [per unit time] that has been adjusted for engine speed.
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#6
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Re: Re: toruqe versus acceleration
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Torque can be applied to a shaft and the shaft does not need to rotate for work to be done. By definition torque is always a force applied at some distance. Power, is work for a given period of time. In order, for power to be applicable a time component is required. With regards to an engine the time component is derived from shaft speed. If a torque is applied to a shaft and the shaft does not rotate power equals zero. Since time is proportional to shaft speed, and a shaft speed of zero implies infinite time.
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#7
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Re: toruqe versus acceleration
Both need to work together
Balance the performance |
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#8
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Re: Re: toruqe versus acceleration
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Work, BY definition requires motion. (at least when discussing an engine), uless your intent is to just develop heat. Obviously by the laws of thermodynamics, the energy is there in some form, but when discussing an engine the work we are interested in is movement. Jim SR Racing |
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#9
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Re: Re: Re: toruqe versus acceleration
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??? "Torque" is a unit of rotational "force." It has nothing to do with "power" or "work". Yes, Horsepower is just a unit, but it is representative of force and time. (or RPM). As posted, HP = TORQUE X RPM / 5252. Again using the recipricating engine, no HP (work) is done unless motion (RPM) is present. Jim SR Racing |
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#10
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Re: Re: Re: Re: toruqe versus acceleration
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Torque is a rotational force but it is directly proportional to work for a given number of revolutions (time independent). That is for one revolution 1 lb-ft of torque will result in 6.28 ft-lb of work, or a 2 lb-ft torque results in 12.56 ft-lb of work. Power is going to be torque and revolutions per unit time, or from above simply work per unit time (not force and time; but force, distance, and time). Also, by saying horsepower is just a unit, my point is that it should not be substituted for the word “power”.
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#11
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[img=http://img220.exs.cx/img220/502/tqhp9je.th.jpg]
i think it looks perdy...except i don't think i have the turbo setup correctly. edit: yea pic was big but now you can see why there alot of "0"s ![]() more edit:I took the race ported flow file and scaled up the flow to match the increased size of the ports over the origional. Its also iinteresting to note that by increasing the flow of the turbo charger the HP decreases. i don't know how one would properly setup the turbo on this.
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I disregard my perceived image in the persuit of knowledge. |
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#12
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Re: toruqe versus acceleration
Theres a lot of "0"s on that grapgh!
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Connecting the Auto Enthusiasts
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#13
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Re: Re: Re: Re: Re: toruqe versus acceleration
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Yes, Torque is rotational force that is proportional to work (HP) in the provided formula. Its (torque) presence though, does not mean any work is being done. For example a steam engine produces maximum torque at 0 RPM. All the energy is expended as heat. Thus, 0 HP. In this engine scenario, the term "horsepower" can certainly be substituted for the word "power". As could be "Watts" or BTU/Hr, or even "pound feet per minute". They are all the same. Simply "units" that represent power. Jim SR Racing |
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#14
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Re: Re: Re: Re: Re: Re: toruqe versus acceleration
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Power = Torque x RPM / 5252 is only applicable when power is in “hp” and torque is in ”lb-ft”. The 5252 comes from converting revolutions to radians, minutes to seconds, and lb-ft / s to hp. The general equation for power is actually: Power = Torque x Shaft-Speed (P=Tn)
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#15
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Re: Re: Re: Re: Re: Re: Re: toruqe versus acceleration
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But in a practical engine example we are only interested in work at the flywheel. Let's assume an electrical engine. If 1000 watts of electrical power were used at the input, some power would result as heat and some as mechanical movement. While this is a 1.35 HP use of energy, it would not result in 1.35 HP of mechanical power. But the total power in vs the total power out would be equal. Maybe 1 HP in output shaft work and another .35HP (or 890 BTU) in heat loss. (Both frictional and electrical resistance.) I think we have drifted from the thread slightly , but it was a nice exercise. As an EE and now owner operator of a chassis dyno and two engine dynos, similar discusions come up with my customers. I try not to get into the conservation of energy laws, since it really doesn't help them much in understanding when to shift from 3rd gear to 4th on the drag strip, or what engine they should use to pull a trailer with. Thanks Jim SR Racing |
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