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Re: Stoichiometry...
Alright, here it is...
30 mol NH3; 17g/mol NH3; so you have 30 x 17 = 510g NH3
According to your equation, 17.4g (or 1 mol) of NH3 produces 1 mol Ammonium Sulfate. And 1 mol Al. Sulfate is 132g. Thus...
510g NH3 x 1 mol (NH4)2 SO4......x 132g (NH4)2 SO4
..................17.4g NH3..................1 mol (NH4)2 SO4....So 30 mol NH3 made 3869 g of (NH4)2 SO4
But you need moles, so 3869/132 will give you 7.6 mol
Hope this helps!
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