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Originally Posted by UncleBob
ah....CURRENT is higher? Current to what? To the computer? How?
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Actually he is correct. Depending upon the charge rate and how he is charging it. The voltage at the charger connections can be much higher than 12.6 (a fully charged battery) And the computer is connected (along with a few other devices) so, it is law that I = E/R.
The load remains the same, the voltage is higher and thus the current to the computer is higher. Nothing secret about this. However, the risk while finite, is small. The manufacturers were well aware of this and the ECM can handle it fine. There is also some remote possibilty of large voltage spikes due to inductive loads in the circuit. This can occur when connecting and disconnecting a charger. (It doesn't matter whether you disconnect the negative or positve terminals first.) However, the manufacturers also prepped for this with decoupling capacitors in all the high impedance devices like the ECM. So it is also a very small risk.
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If current is higher to the computer, its higher to everything else in the circuit. So IF thats the case, then everything else is at risk.
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And it is., albeit a small risk.
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I'm leading you. I want to see a better answer. What is the REAL risk here, and what causes it, specifically.
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I just gave it to you. AND, all other things being equal... it is not a bad idea to disconnect the battery when charging. But almost not worth the effort.
Jim
EE/ME