Thread: Rim Inertia
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Old 03-04-2002, 10:40 AM
ivymike1031 ivymike1031 is offline
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Quote:
Originally posted by fritz_269
There are four wheels, so we just add four times the wheel inertia to the translational intertia (3000 lbs). So:
Car w/ 15's -> I = 3093.84 lb*ft^2
Hey Fritz,

correct me if I'm wrong here, but you can't add 3000lbm + 93.84lbm.ft^2 and get 3093.84lbm.ft^2... I think you'll see what I'm saying...
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