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Re: Math Help Please
Well GS, I'm not good at explaining but i'll give it a shot...
what your doing is derivables (something we're learning in grade 2 calculus here in Ontario)
Anyways here it goes....
h'=2(-4.9)+22.8, which is the drivable of your previous euation.
Complete it and you have h'=-9.8+22.8
Now you get a max or min when the derivable equals 0 so....0=-9.8t=22.8
Bring the 22.8 on the other side and you get -22.8=-9.8t
t=-22.8/-9.8....which t=2.33
Now you have the time when your going to have a max or min, so replace the value of "t" in the orginal equation
h=-4.9(2.33squared)+22.8(2.33)...And you get the value of h=26.52
Now the max or min of a projectile is in the middle, since you have the time where you reach that maximum or minimum, double it and you have the duration of the trajectory...
Hope thats clear enough
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