Logic Problems!
I-Tech
03-24-2003, 05:27 AM
here are the rules. i will start off with posting one logic problem. then, whoever answers it first can post their logic problem. if the person who answered the logic problem does not post another one within a day, than his turn is lost and it goes to the person who posts a logic problem first. if a logic problem is not answered within 3 days, then the poster of the problem has to post the answer, if he doesnt, then another person (the first one to do so) can post a logic problem. posters can post as many hints as they want. if on the third day no one has answered the question, the poster must post 2-3 hints to the answer, if he does not, the problem is eliminated.
here is the logic problem:
On a train, Smith, Robinson, and Jones are the fireman, brakeman, and the engineer, but NOT respectively. Also aboard the train are three businessmen who have the same names: a Mr. Smith, a Mr. Robinson, and a Mr. Jones.
Mr. Robinson Lives in Detroit.
The brakeman lives exactly halfway between Chicago and Detroit
Mr. Jones earns exactly $20,000 per year.
The brakeman's nearest neighbor, one of the passengers, earns exactly three times as much as the brakeman.
Smith beats the fireman in billiards.
The passenger whose name is the same as the brakeman's lives in Chicago.
Who is the engineer?
here is the logic problem:
On a train, Smith, Robinson, and Jones are the fireman, brakeman, and the engineer, but NOT respectively. Also aboard the train are three businessmen who have the same names: a Mr. Smith, a Mr. Robinson, and a Mr. Jones.
Mr. Robinson Lives in Detroit.
The brakeman lives exactly halfway between Chicago and Detroit
Mr. Jones earns exactly $20,000 per year.
The brakeman's nearest neighbor, one of the passengers, earns exactly three times as much as the brakeman.
Smith beats the fireman in billiards.
The passenger whose name is the same as the brakeman's lives in Chicago.
Who is the engineer?
crab
03-24-2003, 11:42 AM
Smith?
YogsVR4
03-24-2003, 01:26 PM
The answer is Smith.
Try this one.
How much wood would a woodchuck chuck if a woodchuck could chuck wood?
Try this one.
How much wood would a woodchuck chuck if a woodchuck could chuck wood?
Pikachoo
03-25-2003, 09:17 AM
A woodchuck would chuck as much wood as a woodchuck could, if a woodchuck could chuck wood...
Am I right??? If not then ignore the problem below....
As a gameshow finalist you can select from mystery boxes - X,Y, and Z. One of the boxes contains
a million dollars, and two of them are empty. After you have made a choice, the show host opens one of the boxes that you did not choose, and it is empty. You are offered a choice to either stay with the box you originally chose, or switch to the other unopened box.
Are your chances better if you stay with your original choice or if you switch, or does it
matter? Why?
Am I right??? If not then ignore the problem below....
As a gameshow finalist you can select from mystery boxes - X,Y, and Z. One of the boxes contains
a million dollars, and two of them are empty. After you have made a choice, the show host opens one of the boxes that you did not choose, and it is empty. You are offered a choice to either stay with the box you originally chose, or switch to the other unopened box.
Are your chances better if you stay with your original choice or if you switch, or does it
matter? Why?
YogsVR4
03-25-2003, 09:56 AM
Originally posted by Pikachoo
As a gameshow finalist you can select from mystery boxes - X,Y, and Z. One of the boxes contains
a million dollars, and two of them are empty. After you have made a choice, the show host opens one of the boxes that you did not choose, and it is empty. You are offered a choice to either stay with the box you originally chose, or switch to the other unopened box.
Are your chances better if you stay with your original choice or if you switch, or does it
matter? Why?
If you stay with your choice you win at a 1 in 3 rate. If you trade, you will win at a 2 out of 3 rate.
Try this one.
A bird in the hand is worth two in the bush.
You can kill two birds with one stone.
So - is it worth letting go of the bird to grab the stone and get two birds? The dilema being are two dead birds worth one live bird (assuming it wasn't a dead bird in the hand - otherwise you'd have the simple answer of dropping the dead bird, picking up the stone and getting two more dead birds.)
Consider your answer with the stone rolling or sitting still and gathering moss.
As a gameshow finalist you can select from mystery boxes - X,Y, and Z. One of the boxes contains
a million dollars, and two of them are empty. After you have made a choice, the show host opens one of the boxes that you did not choose, and it is empty. You are offered a choice to either stay with the box you originally chose, or switch to the other unopened box.
Are your chances better if you stay with your original choice or if you switch, or does it
matter? Why?
If you stay with your choice you win at a 1 in 3 rate. If you trade, you will win at a 2 out of 3 rate.
Try this one.
A bird in the hand is worth two in the bush.
You can kill two birds with one stone.
So - is it worth letting go of the bird to grab the stone and get two birds? The dilema being are two dead birds worth one live bird (assuming it wasn't a dead bird in the hand - otherwise you'd have the simple answer of dropping the dead bird, picking up the stone and getting two more dead birds.)
Consider your answer with the stone rolling or sitting still and gathering moss.
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