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boost question


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krisw
05-05-2005, 04:48 PM
ok heres one for ya... charles law (which has to do with gas flow characteristics) says that "The pressure and temperature of a gas are directly proportional to each other when the volume is held constant, and the volume and temperature are directly proportional when the pressure is held constant."
so since volume and temperature are directly proportional when pressure is held constant, then if temperature is also held constant then volume should remain constant as well. which tells me that assuming 100% efficiency of supercharger (which i know isnt possible, but has been an aspect of this question for this entire thread) then there will be no temperature difference, so therefore if the pressure is the same, and the temperature of the air is the same, then the flow must be the same.

SkylineUSA
05-06-2005, 01:21 AM
So you can make a supercharger a 100% efficient, right?

Of course volume and temp are related, we have all been saying that.

Show my two different superchargers of different sizes that are both 100% efficient, and then you are right. Other than that, you are dead wrong!

krisw
05-06-2005, 05:46 AM
oh my god are you kidding me, thats been the point of this the entire time. in no way am i claiming that there is a 100% effiecient supercharger, all im trying to do is take variables out of the equation and get to the simples form. as a matter of fact i have phrased the question this exact same way several times and you have told me im wrong. actually let me go back and quote it...
-my question "so would jayson be correct in saying that in theory, without taking heat and thermal expansion and whatever into account, the m90 and the m45 would be flowing the exact same amount of air at 10psi?"
- your response "Of course not, you still have volume."
- me "ok someone asked a similar question to this on another board that im on and it was answered in a logical way within a couple posts. as i suspected, the 2 superchargers at 10psi will flow the exact same amount of air (assuming perfect world scenarios aka 100% efficiency and such)"

-you "Wrong!

It would be impossible to achieve that!"

-me "obviously its physically impossible to achieve 100% efficiency, im not trying to find a supercharger that will do that. im just saying that assuming 100% efficiency they would flow the same amoutn of air."

you- "I see how you are trying to look at it, but its not the right way. If two different blowers are 100% efficient, and both are blowing 10psi in the same intake, are they at the same RPM? Where in the rev range do they make 10psi, at the same point, with same volume, if that is the case they are the same blower, and not of different sizes that your mind is so wrapped up on. That is my point. You want the laws of physics to agree with what you are saying, in that aspect you are making a mockery of physics?"

so there ya go, asked several times, and each time you told me im wrong, but now im right? ok... make up your mind. and for all of you who told me im stupid and whatnot, why dont you suck a dick and learn some shit before you start posting... all you can say whatever you like about anything, but if you have no actual knowledge to back it up it doesnt mean shit. i appreciate skylineusa for having an intelligent arguement with me and trying to help me with my problem. but for the rest of you :loser:

iamoliver
09-07-2005, 02:23 PM
this dud is jsut retarted, man look everyone give me a sign if you understand what im trying to say.

u got 45 cfm/rev on one supercharger, 90 on teh other
u run the m45 at lets say 10psi, it will charge the intake with the same combustable volume of air as the m90 under 5 psi. because 45 cfm@10 psi is the same as 90cfm at 5 psi. the same amount of air charge will fill the intake manifold. the m45 , higher density at a less ammount, or the m90, a lower density at a larger ammount. same thing. the m90 now, regarding to what i just said, since it only needs to creat half as much boost only needs to run half as fast, so the guy talking about a lesser speed on the m90 to create teh same power was right. now if you run the m90 at the 10psi, it will be twice as powerful, right?
so yes, twice the cfm airflow, at the same pis, will create twice the ammount of air at the same density , for twice the power. i dumbed it down as best i could, hope it helps

-> Mason <-
09-08-2005, 10:06 PM
since the bigger turbo/supercharger is forcing more air in it's giving the engine more oxygen to work with, and isn't having to work as hard to do so....a smaller turbo/supercharger is having to push in the same amount of oxygen but is having to push harder, which means more revolutions, to get the same output.....i don't understand how that's hard to grasp....

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